# Give:

AB = 6x + 5

AD = 3x + 3

BC = x - 2

Line segment BC is congruent Line segment DC,

Then CD=BC = x - 2

Perimeter of the kite of ABCD equals to AB + AD + BC + CD:

Then,

p = 6x + 5 + 3x + 3 + x - 2 + x - 2

simplify:

p = 11x + 4

Olease R.

asked • 10/08/20
More

AB = 6x + 5

AD = 3x + 3

BC = x - 2

Line segment BC is congruent Line segment DC,

Then CD=BC = x - 2

Perimeter of the kite of ABCD equals to AB + AD + BC + CD:

Then,

p = 6x + 5 + 3x + 3 + x - 2 + x - 2

simplify:

p = 11x + 4

Janelle S. answered • 10/08/20

Tutor

4.7
(26)
Penn State Grad for ME, Math & Test Prep Tutoring (10+ yrs experience)

Since lineAB and lineAD are congruent, their lengths are equal. Since lineBC and lineDC are congruent, their lengths are equal.

Set AB equal to AD to solve for x:

AB = AD

6x + 5 = 3x + 3

3x = -2

x = -2/3

Now plug in x into each equation to find the length of each line:

AB = 6x + 5 = 6(-2/3) + 5 = 1

AD = 3x + 3 = 3(-2/3) + 3 = 1

BC = x - 2 = (-2/3) - 2 = -8/3

DC = BC = -8/3

Add all four lengths to find the perimeter of the kite:

P = AB + AD + BC + DC = 1 + 1 + (-8/3) + (-8/3) = -10/3

The only issue is that a length should never be negative. Are you sure those are the correct equations?

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Olease R.

its x-210/08/20